Chapter 17 Problem 17-7
a. Service hours method:
960,000 – 60,000
Depreciation rate per hour = ---------------------------- = 112.50
8,000 hours
2008 (1,000 hours x 112.50) 112,500
2009 (2,000 hours x 112.50) 225,000
b. Sum of years’ digits:
Sum of half years = 45
2008 (9/45 x 900,000 x 3/6) 90,000
2009 January 1 – March 31 (9/45 x 900,000 x 3/6) 90,000
April 1 – September 30 (8/45 x 900,000) 160,000
October 1 – December 31 (7/45 x 900,000 x 3/6) 70,000
320,000
No comments:
Post a Comment